



The bond line formula for a compound is a simplified representation of its molecular structure without showing individual hydrogen atoms attached to carbon atoms. It provides a clearer depiction of the backbone structure made by carbon atoms and any functional groups or substituents.
The given compound is HOCH(CN)2, which can be expanded to show:
To determine the correct bond line structure:
The correct bond line structure will show a central carbon atom with lines representing the bonds to the hydroxyl and cyano groups. Let's examine the options:
Therefore, the correct bond line formula is as represented in Fig 4.
This formula accurately depicts the structure as:
Hence, the answer is correctly represented by Fig 4.
The given compound is \( \text{HOCH(CN)}_2 \). This indicates a carbon atom bonded to a hydroxyl group (\(-\text{OH}\)) and two cyano groups (\(-\text{CN}\)).
The correct bond-line formula for this structure is represented by option (4).
Explanation: The central carbon atom is bonded to one hydroxyl group (\(-\text{OH}\)) and two cyano groups (\(-\text{CN}\)). This structure matches the representation of option (4), showing two cyano groups attached to the central carbon atom along with the hydroxyl group.
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)

Cobalt chloride when dissolved in water forms pink colored complex $X$ which has octahedral geometry. This solution on treating with cone $HCl$ forms deep blue complex, $\underline{Y}$ which has a $\underline{Z}$ geometry $X, Y$ and $Z$, respectively, are



What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)