The main product of the reaction of CH\(_3\)CONH\(_2\) with Br\(_2\) in aqueous potassium hydroxide medium is
Show Hint
- CH\(_3\)-CH\(_2\)-NH\(_2\)
- CH\(_3\)Br
- CH\(_3\)CONHBr
- CH\(_3\)NH\(_2\)
The Correct Option is D
Solution and Explanation
Hoffmann bromamide degradation.
Step 2: Detailed Explanation:
R-CONH\(_2\) + Br\(_2\) + 4KOH \(\rightarrow\) R-NH\(_2\) + 2KBr + K\(_2\)CO\(_3\) + 2H\(_2\)O
CH\(_3\)CONH\(_2\) \(\rightarrow\) CH\(_3\)NH\(_2\)
Step 3: Final Answer:
Product is CH\(_3\)NH\(_2\) (methylamine).
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