Step 1: The relationship between the electric field \( E \) and the magnetic field \( B \) in a plane electromagnetic wave is given by: \[ E = c B \] where \( c = 3 \times 10^8 \, {m/s} \) is the speed of light.
Step 2: Given that the amplitude of the magnetic field is \( 2 \times 10^{-8} \, {T} \), we can calculate the amplitude of the electric field as: \[ E = (3 \times 10^8) \times (2 \times 10^{-8}) = 6 \, {V/m}. \]
Step 3: Since the magnetic field is along the \( \hat{j} \)-axis (the \( y \)-axis), the electric field must be perpendicular to it and, therefore, must be along the \( x \)-axis.
A thermodynamic system is taken from an original state D to an intermediate state E by the linear process shown in the figure. Its volume is then reduced to the original volume from E to F by an isobaric process. The total work done by the gas from D to E to F will be:
