Question:
The magnetic energy stored in an inductor of inductance \(4\,\text{H}\) carrying a current of \(1.5\) A is
The magnetic energy stored in an inductor of inductance \(4\,\text{H}\) carrying a current of \(1.5\) A is
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Magnetic energy in an inductor is one half L I squared.
Updated On: Oct 1, 2026
- \(4.5\) mJ
- \(3\,μ\text{J}\)
- \(45\,μ\text{J}\)
- \(4500\) mJ
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The Correct Option is D
Solution and Explanation
Step 1: Understand the concept
The energy stored in the magnetic field of an inductor carrying a current \(I\) is \(U = \dfrac{1}{2}LI^2\).
Step 2: Substitute
\(L = 4\) H and \(I = 1.5\) A.
Step 3: Compute
\[ U = \frac{1}{2}\times4\times(1.5)^2 = 2\times2.25 = 4.5\ \text{J} \]
Step 4: Convert units
\(4.5\ \text{J} = 4500\ \text{mJ}\), option (D). The value 4.5 mJ is off by a factor of 1000 because it treats 4.5 as if it were already in millijoules.
Final Answer:
The energy is 4.5 J, which is 4500 mJ. This is option (D). \[ \boxed{\text{(D) }4500\ \text{mJ}} \]
The energy stored in the magnetic field of an inductor carrying a current \(I\) is \(U = \dfrac{1}{2}LI^2\).
Step 2: Substitute
\(L = 4\) H and \(I = 1.5\) A.
Step 3: Compute
\[ U = \frac{1}{2}\times4\times(1.5)^2 = 2\times2.25 = 4.5\ \text{J} \]
Step 4: Convert units
\(4.5\ \text{J} = 4500\ \text{mJ}\), option (D). The value 4.5 mJ is off by a factor of 1000 because it treats 4.5 as if it were already in millijoules.
Final Answer:
The energy is 4.5 J, which is 4500 mJ. This is option (D). \[ \boxed{\text{(D) }4500\ \text{mJ}} \]
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