Question:

The logical statement \(\sim [(p\rightarrow q)\leftrightarrow (p\wedge \sim q)]\) is

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Use the fact that the negation of an implication is the conjunction of the antecedent with the negated consequent.
Updated On: Nov 12, 2026
  • a fallacy
  • equivalent to \(p\wedge q\)
  • equivalent to \(p\vee q\)
  • a tautology
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The Correct Option is D

Solution and Explanation

Step 1: Understanding the Concept
The negation of an implication is \(\sim(p\rightarrow q)\equiv p\wedge\sim q\). So \(p\rightarrow q\) and \(p\wedge\sim q\) always have opposite truth values.

Step 2: Biconditional
A biconditional is true only when both sides have the same truth value. Here the two sides always differ, so \((p\rightarrow q)\leftrightarrow(p\wedge\sim q)\) is always false, i.e. a contradiction.

Step 3: Negate
The negation of a contradiction is always true, so \(\sim[(p\rightarrow q)\leftrightarrow(p\wedge\sim q)]\) is a tautology.

Final Answer:
The given statement is a tautology. \[ \boxed{\text{(D) }\text{a tautology}} \]
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