Question

The lid of a rectangular box of sides 40 cm by 10 cm is sealed all round with tape. What is the length of the tape required?

Answer 1

\(\text{Total length of tape required} = \text{Perimeter of rectangle }\)
= \(2\) \((length + breadth)\) 
= \(2 (40 + 10)\) 
= \(2 \times 50\) 
= \(100\) \(cm\) 
= \(1\) \(m\)

Thus, the total length of tape required is \(100\) \(cm\) or \(1\) \(m\). 

Read more: Perimeter