Since the \(4\) rows of wires are needed.
Therefore the total length of wires is equal to \(4 \) times the perimeter of rectangle.
\(\text{Perimeter of field} = 2 \times (length + breadth)\)
= \(2 \times (0.7 + 0.5)\)
= \(2 \times 1.2 = 2.4 \;km\)
= \(2.4 \times 1000\) \(m\)
= \(2400\) \(m\)
Thus, the length of wire = \(4 \times 2400\)
= \(9600\) \(m\)
= \(9.6\) \(km\)
Write first five multiples of :
| Column 1 | Column 2 |
| (i) 35 | (a) Multiple of 8 |
| (ii) 15 | (b) Multiple of 7 |
| (iii) 16 | (c) Multiple of 70 |
| (iv) 20 | (d) Factor of 30 |
| (v) 25 | (e) Factor of 50 |
| (f) Factor of 20 |

A table-top measures 2 m 25 cm by 1 m 50 cm. What is the perimeter of the table-top?
Write first five multiples of :
| Column 1 | Column 2 |
| (i) 35 | (a) Multiple of 8 |
| (ii) 15 | (b) Multiple of 7 |
| (iii) 16 | (c) Multiple of 70 |
| (iv) 20 | (d) Factor of 30 |
| (v) 25 | (e) Factor of 50 |
| (f) Factor of 20 |