Question

A table-top measures 2 m 25 cm by 1 m 50 cm. What is the perimeter of the table-top?

Answer 1

Length of table top = \(2\) \(m\) \(25\) \(cm\) 
= \(2.25\) \(m\) 
Breadth of table top  = \(1\) \(m\) \(50\) \(cm\) 
= \(1.50\) \(m\) 
Perimeter of table top = \(2\) \(\times\) \((length + breadth)\) 
= \(2 \times (2.25 + 1.50)\) 
= \(2 \times 3.75 = 7.50\) \(m\)

Thus, the perimeter of table top is \(7.5\) \(m\). 

Answer 2

To find the perimeter of the tabletop, we first need to convert the given dimensions into a consistent unit. We will use meters.
(1) The length of the table-top is 2m 25cm. Converting cm to m:
\(2 \, \text{m} + 25 \, \text{cm} = 2 \, \text{m} + 0.25 \, \text{m} = 2.25 \, \text{m}\)

(2) The width of the table-top is 1m 50cm. Converting cm to m:
\(1 \, \text{m} + 50 \, \text{cm} = 1 \, \text{m} + 0.50 \, \text{m} = 1.50 \, \text{m}\)

Now, the length l and width w of the table-top are:
\(l = 2.25 \, \text{m}\)
\(w = 1.50 \, \text{m}\)

The perimeter P of a rectangle is given by the formula:
\(P = 2(l + w)\)
Substituting the values:
\(P = 2(2.25 + 1.50)\)
\(P = 2(3.75)\)
\(P = 7.50 \, \text{m}\)

So, the answer is 7.5m