Using the formula for the length of the common chord of two intersecting circles:
\[
L = 2 \sqrt{r_1^2 - d^2}
\]
Where \( r_1 = 20 \) cm (radius of the larger circle), \( r_2 = 15 \) cm (radius of the smaller circle), and \( d = 25 \) cm (distance between the centers). The length of the common chord is:
\[
L = 2 \sqrt{20^2 - 25^2} = 2 \sqrt{400 - 625} = 25 \, \text{cm}
\]
Thus, the length of the common chord is 25 cm.