Given : ellipse equation : $\div(x+1)^{2} 9+\div(y-2)^{2} 4=1$ Circle equation : $(x-1)^{2}+(y-2)^{2}=1$ $\therefore$ center of ellipse $=(-1,2)$ $a =3, b =2$ $\therefore$ length of major axis is $6$ $\therefore$ length of minor is $4$ $\Rightarrow$ center of circle is $(1,2$ with radius $r=1)$ $ \Rightarrow $ so, wecanseeindiagramthatthetwoareasdoesnotintersectortoucheachlengthiso $\Rightarrow$ Hence, The length of common chord of the ellipse and circle is Zero(o).