Question:

The least integer satisfying \( \frac{396}{10} - \frac{19-x}{10}<\frac{376}{10} - \frac{19-9x}{10} \) is:

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Be extremely careful with the negative signs before parentheses. A common mistake is forgetting to distribute the minus sign to both terms inside, e.g., $-(19-x) = -19+x$.
Updated On: May 2, 2026
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The Correct Option is C

Solution and Explanation

Concept: To solve a linear inequality involving fractions with a common denominator, we can multiply the entire inequality by that denominator to simplify the expression.
• If $a < b$, then $ka < kb$ for any positive $k$.
• After clearing denominators, group like terms and solve for $x$.

Step 1:
Eliminate the denominators.
Multiply the entire inequality by $10$: \[ 396 - (19 - x) < 376 - (19 - 9x) \]

Step 2:
Simplify both sides.
\[ 396 - 19 + x < 376 - 19 + 9x \] \[ 377 + x < 357 + 9x \]

Step 3:
Solve for $x$.
Subtract $x$ and $357$ from both sides: \[ 377 - 357 < 9x - x \] \[ 20 < 8x \] \[ x > \frac{20}{8} \Rightarrow x > 2.5 \]

Step 4:
Find the least integer.
The integers satisfying $x > 2.5$ are $\{3, 4, 5, \dots\}$. The least integer is $3$.
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