Question:

The IUPAC name of an element with atomic number \( 119 \) is:

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To remember the rules: if a root ends in 'n' (like enn) and the suffix is 'ium', you keep both 'n's. However, if a root ends in 'i' (like bi or tri) and is followed by 'ium', you drop one 'i' (e.g., Ununtrium, not Ununtriiium).
Updated On: Jun 3, 2026
  • Ununennium
  • Unnilennium
  • Unununium
  • ununoctium
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The Correct Option is A

Solution and Explanation

Concept: For elements with atomic numbers greater than 100, IUPAC established a systematic naming convention based on the numerical roots of the digits in the atomic number. The roots are: {|c|c|c|c|c|c|c|c|c|c|} 0 & 1 & 2 & 3 & 4 & 5 & 6 & 7 & 8 & 9
nil & un & bi & tri & quad & pent & hex & sept & oct & enn
The name is constructed by putting the roots together in order of the digits and adding the suffix "-ium".

Step 1:
Identify the digits of the atomic number
The atomic number given is \( 119 \). The digits are: \( 1 \), \( 1 \), and \( 9 \).

Step 2:
Match each digit to its corresponding IUPAC numerical root.
* Digit \( 1 \): un * Digit \( 1 \): un * Digit \( 9 \): enn

Step 3:
Assemble the name and add the suffix.
Combining the roots: un + un + enn Adding the suffix: un + un + enn + ium Final Name: Ununennium
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