Question:
The ionic conductance of Ba\(^{2+}\) and Cl\(^{-}\) are respectively 127 and 76 ohm\(^{-1}\) cm\(^2\) at infinite dilution. The equivalent conductance (inohm\(^{-1}\) cm\(^2\)) of BaCl\(_2\) at infinite dilution will be:
The ionic conductance of Ba\(^{2+}\) and Cl\(^{-}\) are respectively 127 and 76 ohm\(^{-1}\) cm\(^2\) at infinite dilution. The equivalent conductance (inohm\(^{-1}\) cm\(^2\)) of BaCl\(_2\) at infinite dilution will be:
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The equivalent conductance of a salt at infinite dilution is the sum of the ionic conductances of its constituent ions.
Updated On: Apr 22, 2026
- 139.5
- 203
- 279
- 101.5
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The Correct Option is B
Solution and Explanation
Step 1: Understanding the ionic conductance at infinite dilution.
The equivalent conductance at infinite dilution for a salt like BaCl\(_2\) is the sum of the ionic conductances of the ions: \[ \Lambda^0_{BaCl_2} = \Lambda^0_{Ba^{2+}} + \Lambda^0_{Cl^-} \]
Step 2: Substituting the given values.
Given
\( \Lambda^0_{Ba^{2+}} = 127 \, \text{ohm}^{-1}\text{cm}^2 \) and,
\( \Lambda^0_{Cl^-} = 76 \, \text{ohm}^{-1}\text{cm}^2 \),
we add them:
\[ \Lambda^0_{BaCl_2} = 127 + 76 = 203 \, \text{ohm}^{-1}\text{cm}^2 \]
Step 3: Conclusion.
The correct answer is (2) 203
The equivalent conductance at infinite dilution for a salt like BaCl\(_2\) is the sum of the ionic conductances of the ions: \[ \Lambda^0_{BaCl_2} = \Lambda^0_{Ba^{2+}} + \Lambda^0_{Cl^-} \]
Step 2: Substituting the given values.
Given
\( \Lambda^0_{Ba^{2+}} = 127 \, \text{ohm}^{-1}\text{cm}^2 \) and,
\( \Lambda^0_{Cl^-} = 76 \, \text{ohm}^{-1}\text{cm}^2 \),
we add them:
\[ \Lambda^0_{BaCl_2} = 127 + 76 = 203 \, \text{ohm}^{-1}\text{cm}^2 \]
Step 3: Conclusion.
The correct answer is (2) 203
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