Question:

The incorrect statement from the following with respect to carbohydrates is :

Show Hint

Remember:
  • All monosaccharides are reducing sugars.
  • Oligosaccharides may contain same or different monosaccharide units.
  • Glucose shows mutarotation because cyclic and open-chain forms coexist.
Updated On: Jun 3, 2026
  • All monosaccharides are reducing sugars.
  • The monosaccharide units obtained from hydrolysis of oligosaccharides are always the same.
  • Starch and cellulose are typical examples of polysaccharides, which are very high molecular weight compounds of more than ten monosaccharide units.
  • Open chain and cyclic structures co-exist at equilibrium that are responsible for certain properties as in the case of D-(+)-glucose.
Show Solution
collegedunia
Verified By Collegedunia

The Correct Option is B

Solution and Explanation

Concept: Carbohydrates are polyhydroxy aldehydes or ketones or compounds that produce them upon hydrolysis. They are classified into:
  • Monosaccharides
  • Oligosaccharides
  • Polysaccharides
Reducing sugars contain a free aldehydic or ketonic group capable of reducing Fehling’s solution or Tollens’ reagent.

Step 1:
Checking Statement (1). All monosaccharides possess either:
  • Free aldehyde group
  • Or ketone group capable of tautomerisation
Therefore, all monosaccharides act as reducing sugars. Examples: \[ \text{Glucose, fructose, galactose} \] Thus, Statement (1) is correct.

Step 2:
Checking Statement (2). Oligosaccharides may produce:
  • Same monosaccharide units
  • Different monosaccharide units
Example:
  • Sucrose on hydrolysis gives glucose and fructose.
Since the hydrolysis products are not always identical, the statement saying “always the same” is incorrect. Hence, Statement (2) is incorrect.

Step 3:
Checking Statement (3). Polysaccharides contain large numbers of monosaccharide units. Starch and cellulose are classical examples of polysaccharides. They possess: \[ n > 10 \] monosaccharide units and very high molecular masses. Hence, Statement (3) is correct.

Step 4:
Checking Statement (4). Glucose exists in equilibrium between:
  • Open chain structure
  • Cyclic hemiacetal structures
This equilibrium explains phenomena like:
  • Mutarotation
  • Reducing behaviour
Therefore, Statement (4) is also correct. Thus, the incorrect statement is: \[ \boxed{(2)} \]
Was this answer helpful?
0
0

Top CUET Chemistry Questions

View More Questions