Question:

The INCORRECT match in the following is :

Show Hint

Use \(\Delta G^\circ = -RT\ln K\): the signs of \(\Delta G^\circ\) and \(\ln K\) are always opposite.
Updated On: Nov 11, 2026
  • \(\Delta G^\circ = 0,\ K = 1\)
  • \(\Delta G^\circ \lt 0,\ K \lt 1\)
  • \(\Delta G^\circ \gt 0,\ K \lt 1\)
  • \(\Delta G^\circ \lt 0,\ K \gt 1\)
Show Solution
collegedunia
Verified By Collegedunia

The Correct Option is B

Solution and Explanation

\(\Delta G^\circ = -RT\ln K\).
If \(\Delta G^\circ = 0\), \(\ln K = 0\), \(K = 1\): correct.
If \(\Delta G^\circ \gt 0\), \(\ln K \lt 0\), \(K \lt 1\): correct.
If \(\Delta G^\circ \lt 0\), \(\ln K \gt 0\), \(K \gt 1\): correct.
So \(\Delta G^\circ \lt 0\) with \(K \lt 1\) is impossible: option (2) is the incorrect match.
Answer: (2) \(\Delta G^\circ \lt 0,\ K \lt 1\)
Was this answer helpful?
0
0

Top JEE Main Law Of Chemical Equilibrium And Equilibrium Constant Questions

View More Questions