The given equilibrium is:
\(\text{Cr}_2\text{O}_7^{2-} \rightleftharpoons 2\text{CrO}_4^{2-}\)
This is a classic example of a chemical equilibrium that is sensitive to the pH of the solution. Let's analyze the situation to understand why this equilibrium shifts in different pH conditions:
Conclusion: Since the equilibrium shifts to the right in a basic medium (as OH- ions neutralize H+ ions), the correct answer is a basic medium.
The given equilibrium reaction is:
\(\mathrm{Cr_2O_7^{2-}} \rightleftharpoons 2\mathrm{CrO_4^{2-}}\)
This equilibrium can be affected by the pH of the solution. Specifically, this reaction is an example of how pH influences equilibrium according to Le Chatelier's principle.
Explanation:
Justification of the Correct Answer (Basic Medium):
In a basic medium, the equilibrium will shift towards the formation of chromate ions, \(\mathrm{CrO_4^{2-}}\), moving the equilibrium to the right. This is in accordance with Le Chatelier's principle, as the system adjusts to reduce the effect of the added base (hydroxide ions).
Conclusion:
Thus, the equilibrium \(\mathrm{Cr_2O_7^{2-}} \rightleftharpoons 2\mathrm{CrO_4^{2-}}\) is shifted to the right in a basic medium.
A substance 'X' (1.5 g) dissolved in 150 g of a solvent 'Y' (molar mass = 300 g mol$^{-1}$) led to an elevation of the boiling point by 0.5 K. The relative lowering in the vapour pressure of the solvent 'Y' is $____________ \(\times 10^{-2}\). (nearest integer)
[Given : $K_{b}$ of the solvent = 5.0 K kg mol$^{-1}$]
Assume the solution to be dilute and no association or dissociation of X takes place in solution.
Inductance of a coil with \(10^4\) turns is \(10\,\text{mH}\) and it is connected to a DC source of \(10\,\text{V}\) with internal resistance \(10\,\Omega\). The energy density in the inductor when the current reaches \( \left(\frac{1}{e}\right) \) of its maximum value is \[ \alpha \pi \times \frac{1}{e^2}\ \text{J m}^{-3}. \] The value of \( \alpha \) is _________.
\[ (\mu_0 = 4\pi \times 10^{-7}\ \text{TmA}^{-1}) \]