Question:
The hybridization involved in the metal atom of \([CrF_6]^{3-}\) is:
The hybridization involved in the metal atom of \([CrF_6]^{3-}\) is:
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Octahedral complexes, like \([CrF_6]^{3-}\), typically exhibit \( d^2sp^3 \) hybridization.
Updated On: Apr 7, 2026
- \( d^2sp^3 \)
- \( dsp^2 \)
- \( sp^3 \)
- \( sp^2 \)
- \( sp^3d^2 \)
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The Correct Option is A
Solution and Explanation
In the coordination complex \([CrF_6]^{3-}\), the central metal Chromium (Cr\(^3+\)) has an octahedral geometry, which requires \( d^2sp^3 \) hybridization. This means two d-orbitals, one s-orbital, and three p-orbitals combine to form six equivalent hybrid orbitals.
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