Question:

The hardest lanthanide element is

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Half-filled configurations (like 4f$^7$) give extra stability → higher hardness.
Updated On: May 8, 2026
  • Sm
  • La
  • Gd
  • Dy
  • Yb
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The Correct Option is C

Solution and Explanation

Concept: Hardness in lanthanides depends on:
• Number of unpaired electrons
• Strength of metallic bonding
• Lanthanide contraction

Step 1:
Electronic configuration.
Gd: \[ [Xe]\,4f^7 5d^1 6s^2 \]

Step 2:
Special stability.

• Half-filled 4f subshell (4f$^7$)
• Maximum exchange energy
• Strong metallic bonding

Step 3:
Effect.

• Strong bonding → higher hardness
• Greater resistance to deformation

Step 4:
Comparison.
Other lanthanides either:
• Have fewer unpaired electrons
• Or weaker bonding

Step 5:
Final answer. \[ \boxed{Gd} \]
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