Question:

The half-life period of Radium is 3 minutes. Its decay constant is:

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The decay constant \( \lambda \) is inversely related to the half-life period of a radioactive substance.
Updated On: Apr 28, 2026
  • \( 1.5 \, \text{minute}^{-1} \)
  • \( 0.693 \, \text{minute}^{-1} \)
  • \( 0.231 \, \text{minute}^{-1} \)
  • \( 0.5 \, \text{minute}^{-1} \)
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The Correct Option is B

Solution and Explanation

Step 1: Relation between half-life and decay constant
For a first-order reaction, the half-life is related to the decay constant by:
\( t_{1/2} = \frac{\ln 2}{\lambda} \)

Step 2: Substitute given value
Given:
\( t_{1/2} = 3 \, \text{min} \)

So,
\[ \lambda = \frac{\ln 2}{3} \] \[ \lambda = \frac{0.693}{3} \] \[ \lambda = 0.231 \, \text{min}^{-1} \]

Final Answer:
\( \lambda = 0.231 \, \text{min}^{-1} \)
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