The given lens is broken into four parts and rearranged as shown. If the initial focal length is \( f \), then after rearrangement the equivalent focal length is â
Step 1: Understand the lens formula.
For a combination of lenses in series, the equivalent focal length \( \frac{1}{f_{\text{eq}}} = \frac{1}{f_1} + \frac{1}{f_2} + \cdots \).
Step 2: Rearrange the parts of the lens.
When the lens is broken and rearranged, the effective focal length is halved.
Final Answer: \[ \boxed{\frac{f}{2}} \]
Two plano-convex lenses (1 and 2) of glass of refractive index 1.5 have radii of curvature 25cm and 20cm. They are placed in contact with their curved surfaces towards each other and the space between them is filled with liquid of refractive index 4/3. The combination is: 