Question:
The fundamental frequency '\(n\)' of the tuning fork is 288 Hz, it will not resonate with the frequency
The fundamental frequency '\(n\)' of the tuning fork is 288 Hz, it will not resonate with the frequency
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A fork resonates with its fundamental and its integer multiples. 844 is not a multiple of 288.
Updated On: Oct 1, 2026
- \(288\) Hz
- \(576\) Hz
- \(844\) Hz
- \(864\) Hz
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The Correct Option is C
Solution and Explanation
Step 1: Understanding the Concept:
A tuning fork can set up resonance in another body or fork if the driving frequency is the fork's fundamental frequency or one of its overtones. For a vibrating fork the overtones are integer multiples of the fundamental.
Step 2: Key Formula or Approach:
Check whether each given frequency is an integer multiple of 288 Hz.
Step 3: Detailed Explanation:
(A) \(288 = 1\times288\), so it is the fundamental. It resonates.
(B) \(576 = 2\times288\), the second harmonic. It resonates.
(D) \(864 = 3\times288\), the third harmonic. It resonates.
(C) \(844 \div 288 = 2.93\), which is not an integer, so 844 Hz is not in the harmonic series. It will not resonate.
Final Answer:
The fork will not resonate with 844 Hz, option (C). \[ \boxed{844\text{ Hz (C)}} \]
A tuning fork can set up resonance in another body or fork if the driving frequency is the fork's fundamental frequency or one of its overtones. For a vibrating fork the overtones are integer multiples of the fundamental.
Step 2: Key Formula or Approach:
Check whether each given frequency is an integer multiple of 288 Hz.
Step 3: Detailed Explanation:
(A) \(288 = 1\times288\), so it is the fundamental. It resonates.
(B) \(576 = 2\times288\), the second harmonic. It resonates.
(D) \(864 = 3\times288\), the third harmonic. It resonates.
(C) \(844 \div 288 = 2.93\), which is not an integer, so 844 Hz is not in the harmonic series. It will not resonate.
Final Answer:
The fork will not resonate with 844 Hz, option (C). \[ \boxed{844\text{ Hz (C)}} \]
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