Question:

The function $f(x)=x(\sqrt{x+2}+\sqrt{x+1})$ is continuous on

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The domain of $f+g$ is the intersection of the domains of $f$ and $g$.
Updated On: Apr 28, 2026
  • $(-\infty,1]$
  • $[4,\infty)$
  • $[-3,\infty)$
  • $[-1,\infty)$
  • $(-\infty,\infty)$
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The Correct Option is D

Solution and Explanation

Step 1: Concept
A function involving square roots is continuous where the radicands are non-negative.

Step 2: Analysis

For $\sqrt{x+2}$ to be defined: $x+2 \ge 0 \implies x \ge -2$. For $\sqrt{x+1}$ to be defined: $x+1 \ge 0 \implies x \ge -1$.

Step 3: Conclusion

The domain is the intersection of these conditions: $x \ge -1$. Thus, the function is continuous on $[-1, \infty)$. Final Answer: (D)
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