Question:

The function \(f(x)=|x-2|+|x|+|x+2|\) is not differentiable at which points?

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A modulus function \(|x-a|\) is not differentiable at \(x=a\). For a sum of modulus functions, check all such turning points.
Updated On: Jun 6, 2026
  • \(x=-2\)
  • \(x=0\)
  • \(x=2\)
  • \(x=-2,0,2\)
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The Correct Option is D

Solution and Explanation

Concept:
The modulus function \(|x-a|\) is not differentiable at \(x=a\), because its graph has a sharp corner at that point.

Step 1: Write the given function.
\[ f(x)=|x-2|+|x|+|x+2| \]

Step 2: Identify the critical points.

Each modulus term becomes zero at a particular point. For: \[ |x-2| \] critical point is: \[ x=2 \] For: \[ |x| \] critical point is: \[ x=0 \] For: \[ |x+2| \] critical point is: \[ x=-2 \]

Step 3: Differentiability conclusion.

The function may fail to be differentiable at points where any modulus expression changes sign. Thus, \(f(x)\) is not differentiable at: \[ x=-2,0,2 \] \[ \therefore \text{Correct Answer is (D)} \]
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