Question:

The fuel charges for running a train are proportional to the square of the speed generated in miles per hour and cost $48 per hour at 16 miles per hour. The most economical speed if the fixed charges (i.e., salaries etc.) amount to $30 per hour is:

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Economic speed occurs when running cost equals fixed cost.
Updated On: Mar 24, 2026
  • \(10\)
  • \(20\)
  • \(30\)
  • \(40\)
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The Correct Option is B

Solution and Explanation


Step 1:
Fuel cost \(\propto v^2\Rightarrow\) cost \(=kv^2\).
Step 2:
Given \(k=\dfrac{48}{16^2}=0.1875\).
Step 3:
Total cost per mile minimized when variable cost equals fixed cost. \[ v=\sqrt{\frac{30}{0.1875}}=20 \]
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