A wire 34 cm long is to be bent in the form of a quadrilateral of maximum area in which each angle is 90°. What is the maximum area enclosed?
Step 1: With all angles 90°, the figure is a rectangle.
Step 2: For fixed perimeter, area is maximized by a square.
Step 3: Side =34/4=8.5 cm.
Step 4: Maximum area: A=(8.5)²=72.25 cm²