Question:

The frequency of revolution of an electron in the $n^{\text{th}$ orbit of hydrogen atom is

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Radius $n^2$, Velocity $1/n$, Time Period $n^3$, Frequency $1/n^3$.
Updated On: May 12, 2026
  • directly proportional to $n^2$
  • inversely proportional to $n^2$
  • directly proportional to $n^3$
  • inversely proportional to $n^3$
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The Correct Option is D

Solution and Explanation


Step 1: Concept

Frequency $f = v/2\pi r$. In Bohr's model, velocity $v \propto 1/n$ and radius $r \propto n^2$.

Step 2: Meaning

Frequency is the reciprocal of the time period ($f = 1/T$).

Step 3: Analysis

$f \propto \frac{1/n}{n^2} \propto \frac{1}{n^3}$.

Step 4: Conclusion

Frequency of revolution is inversely proportional to $n^3$. Final Answer: (D)
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