Question:
The frequency of electromagnetic waves produced by a charged particle oscillating about its mean position with a frequency of \(10^8\,\text{Hz}\) is
The frequency of electromagnetic waves produced by a charged particle oscillating about its mean position with a frequency of \(10^8\,\text{Hz}\) is
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An oscillating charge radiates electromagnetic waves whose frequency is
\[
\boxed{f_{\text{EM}}=f_{\text{source}}.}
\]
Only the wavelength changes according to
\[
\lambda=\frac{c}{f}.
\]
Updated On: Jul 18, 2026
- \(5\times10^7\,\text{Hz}\)
- \(2\times10^8\,\text{Hz}\)
- \(10^8\,\text{Hz}\)
- \(2.5\times10^8\,\text{Hz}\)
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The Correct Option is C
Solution and Explanation
Step 1: Recall the relation between oscillating charges and electromagnetic waves.
An accelerating (oscillating) charge emits electromagnetic waves having the same frequency as that of the oscillation.
Thus,
\[
f_{\text{EM}}=f_{\text{oscillation}}.
\]
Step 2: Substitute the given value. Given, \[ f_{\text{oscillation}}=10^8\,\text{Hz}. \] Hence, \[ f_{\text{EM}} = 10^8\,\text{Hz}. \] Therefore, \[ \boxed{f_{\text{EM}}=10^8\,\text{Hz}.} \] Hence, the correct option is \(\boxed{(C)}\).
Step 2: Substitute the given value. Given, \[ f_{\text{oscillation}}=10^8\,\text{Hz}. \] Hence, \[ f_{\text{EM}} = 10^8\,\text{Hz}. \] Therefore, \[ \boxed{f_{\text{EM}}=10^8\,\text{Hz}.} \] Hence, the correct option is \(\boxed{(C)}\).
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