Question:
The formula of pentaamminecarbonatocobalt(III) chloride is
The formula of pentaamminecarbonatocobalt(III) chloride is
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For coordination compounds:
- Neutral ligands $\Rightarrow$ no charge contribution
- Balance overall charge to find counter ions
Updated On: Apr 30, 2026
- $[\mathrm{Co(NH_3)_5(CO)}]\mathrm{Cl_2}$
- $[\mathrm{Co(NH_3)_5(CO_3)}]\mathrm{Cl}$
- $[\mathrm{Co(NH_3)_5(CO_3)}]\mathrm{Cl_2}$
- $[\mathrm{Co(NH_3)_5(CO_3)}]\mathrm{Cl_2}$
- $[\mathrm{Co(NH_3)_5(CO_3)}]\mathrm{Cl_3}$
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The Correct Option is B
Solution and Explanation
Concept:
• Ammine ($\mathrm{NH_3}$) is a neutral ligand
• Carbonato ($\mathrm{CO_3^{2-}}$) is a $-2$ charged ligand
• Cobalt(III) $\Rightarrow$ oxidation state $+3$
Step 1: Calculate charge on complex ion.
\[ \text{Charge} = +3 + (0 \times 5) + (-2) = +1 \]
Step 2: Determine counter ions.
Complex ion has charge $+1$, so one $\mathrm{Cl^-}$ is needed.
Step 3: Write final formula.
\[ [\mathrm{Co(NH_3)_5(CO_3)}]\mathrm{Cl} \]
• Ammine ($\mathrm{NH_3}$) is a neutral ligand
• Carbonato ($\mathrm{CO_3^{2-}}$) is a $-2$ charged ligand
• Cobalt(III) $\Rightarrow$ oxidation state $+3$
Step 1: Calculate charge on complex ion.
\[ \text{Charge} = +3 + (0 \times 5) + (-2) = +1 \]
Step 2: Determine counter ions.
Complex ion has charge $+1$, so one $\mathrm{Cl^-}$ is needed.
Step 3: Write final formula.
\[ [\mathrm{Co(NH_3)_5(CO_3)}]\mathrm{Cl} \]
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