Question

The formation of \( \mathrm{O}_{2}^{+}[\mathrm{PtF}_{6}]^{-} \) is the basis for the formation of xenon fluorides because:

• A. $O_{2}$ and $Xe$ have comparable sizes
• B. Both $O_{2}$ and $Xe$ are gases
• C. $O_{2}$ and $Xe$ have comparable ionisation energies
• D. Both (A) and (C)

Hint:

Xenon chemistry started when its I.E. was found to match Oxygen's I.E.

Answer 1

The Correct Option is D

Step 1: Concept
Neil Bartlett noticed the similarity between Oxygen and Xenon properties.
Step 2: Analysis
The first ionization energy of $Xe$ ($1170 kJ/mol$) is very close to that of $O_{2}$ ($1175 kJ/mol$). Their molecular/atomic diameters are also nearly identical.
Step 3: Conclusion
Due to comparable sizes and ionization energies, $Xe$ was expected to react similarly to $O_{2}$.
Final Answer: (D)