Question:

The following reaction method
fe dark
is not suitable for the preparation of the corresponding haloarene products, due to high reactivity of halogen, when X is :

Updated On: May 1, 2026
  • F
  • I
  • Cl
  • Br
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The Correct Option is A

Solution and Explanation

In the given chemical reaction, we are considering the preparation of haloarenes using a halogenation method. This involves treating an aromatic compound with halogens in the presence of a catalyst like iron (Fe) in dark conditions. The reaction depicted is:

The options for the halogen X are F (Fluorine), I (Iodine), Cl (Chlorine), and Br (Bromine). The question asks which halogen results in a reaction that is not suitable due to high reactivity.

Let's analyze each option:

  1. Fluorine (F): Fluorine is highly reactive compared to other halogens. Its reaction with aromatic compounds is extremely vigorous and often uncontrollable, leading to unwanted side products or even complete reaction of the aromatic ring. Hence, it is not suitable for the preparation of haloarenes in this context.
  2. Iodine (I): Iodine is the least reactive halogen in this context, often requiring more severe conditions to react, such as the presence of an oxidizing agent. Thus, it doesn’t face the issue of excessive reactivity.
  3. Chlorine (Cl) and Bromine (Br): Both chlorine and bromine are effectively used for the halogenation of benzene rings under controlled conditions and do not exhibit the uncontrolled reactivity demonstrated by fluorine.

Thus, the correct answer is:

  • F (Fluorine), as it is not suitable for this reaction due to its excessively high reactivity.
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