Question:
The following reaction is named as
The following reaction is named as
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Cannizzaro reaction always requires absence of $\alpha$-hydrogen and involves simultaneous oxidation and reduction.
Updated On: May 1, 2026
- Reimer-Tiemann
- Kolbe-Schmitt
- Cannizzaro
- Gattermann
- Aldol
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The Correct Option is C
Solution and Explanation
Concept:
Cannizzaro reaction occurs with aldehydes lacking $\alpha$-hydrogen.
In presence of strong base, one aldehyde group is oxidized to carboxylate and the other is reduced to alcohol.
Step 1: {The starting compound.}
Phthalaldehyde contains two \( -CHO \) groups attached to a benzene ring. These aldehyde groups do not have any $\alpha$-hydrogen.
Step 2: {Identify reaction conditions.}
Presence of strong base \( KOH \) and heat indicates: \[ \text{Cannizzaro reaction} \]
Step 3: {Apply intramolecular Cannizzaro reaction.}
Since two aldehyde groups are in the same molecule: - One \( -CHO \) is oxidized to \( -COOK \) - Other \( -CHO \) is reduced to \( -CH_2OH \)
Step 4: {Final product.}
\[ \boxed{\text{Potassium 2-(hydroxymethyl)benzoate}} \]
Step 1: {The starting compound.}
Phthalaldehyde contains two \( -CHO \) groups attached to a benzene ring. These aldehyde groups do not have any $\alpha$-hydrogen.
Step 2: {Identify reaction conditions.}
Presence of strong base \( KOH \) and heat indicates: \[ \text{Cannizzaro reaction} \]
Step 3: {Apply intramolecular Cannizzaro reaction.}
Since two aldehyde groups are in the same molecule: - One \( -CHO \) is oxidized to \( -COOK \) - Other \( -CHO \) is reduced to \( -CH_2OH \)
Step 4: {Final product.}
\[ \boxed{\text{Potassium 2-(hydroxymethyl)benzoate}} \]
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