Question:
The following graph is obtained for the adsorption of a gas on a metal surface at 300K. What is the value of $x/m$ when the pressure of gas is 2 bar?
The following graph is obtained for the adsorption of a gas on a metal surface at 300K. What is the value of $x/m$ when the pressure of gas is 2 bar?
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Slopes and intercepts in logarithmic plots reveal adsorption constants.
Updated On: Jun 10, 2026
- 100
- 400
- 200
- 10
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The Correct Option is B
Solution and Explanation
Step 1: Concept
Freundlich Adsorption Isotherm: $\log(x/m) = \log k + (1/n) \log P$.
Step 2: Analysis
Given graph slope = 2. $\log(x/m) = \text{intercept} + 2 \log P$. At $P=2$, $\log P \approx 0.3$. Based on provided graph data (intercept, etc.), the calculated $\log(x/m) \approx 2.6 \implies x/m \approx 400$.
Step 3: Conclusion
The value is 400.
Final Answer: (B)
Freundlich Adsorption Isotherm: $\log(x/m) = \log k + (1/n) \log P$.
Step 2: Analysis
Given graph slope = 2. $\log(x/m) = \text{intercept} + 2 \log P$. At $P=2$, $\log P \approx 0.3$. Based on provided graph data (intercept, etc.), the calculated $\log(x/m) \approx 2.6 \implies x/m \approx 400$.
Step 3: Conclusion
The value is 400.
Final Answer: (B)
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