Question:
The figure shows a square loop $L$ of side $5\, cm$ which is connected to a network of resistances.
The whole setup is moving towards right with a constant speed of $1\, cms^{-1}$. At some instant, a part of $L$ is in a uniform magnetic field of $1T$, perpendicular to the plane of the loop. If the resistance of $L$ is $1.7\, \Omega$ , the current in the loop at that instant will be close to :
The figure shows a square loop $L$ of side $5\, cm$ which is connected to a network of resistances.
The whole setup is moving towards right with a constant speed of $1\, cms^{-1}$. At some instant, a part of $L$ is in a uniform magnetic field of $1T$, perpendicular to the plane of the loop. If the resistance of $L$ is $1.7\, \Omega$ , the current in the loop at that instant will be close to :
Updated On: Apr 1, 2026
- $115\, \mu A$
- $170 \, \mu A$
- $60\, \mu A$
- $150\, \mu A$
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The Correct Option is B
Solution and Explanation
Since it is a balanced wheatstone bridge, its equivalent resistance $ = \frac{4}{3} \Omega$
$ \varepsilon = B \ell v = 5 \times 10^{-4} V$
So total resistance
$R = \frac{4}{3} + 1.7 \approx 3\Omega $
$ \therefore \; i \frac{\varepsilon}{R} \approx 166 \mu A \; \approx \; 170 \mu A $
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Concepts Used:
Electromagnetic Induction
Electromagnetic Induction is a current produced by the voltage production due to a changing magnetic field. This happens in one of the two conditions:-
- When we place the conductor in a changing magnetic field.
- When the conductor constantly moves in a stationary field.
Formula:
The electromagnetic induction is mathematically represented as:-
e=N × d∅.dt
Where
- e = induced voltage
- N = number of turns in the coil
- Φ = Magnetic flux (This is the amount of magnetic field present on the surface)
- t = time
Applications of Electromagnetic Induction
- Electromagnetic induction in AC generator
- Electrical Transformers
- Magnetic Flow Meter