Question:

The feasible region represented by the given constraints $2x + 3y \ge 12, -x + y \le 3, x \le 4, y \ge 3$ is denoted by

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Feasible region = common shaded region satisfying all inequalities.
Updated On: Apr 26, 2026
  • $\text{S}_1$
  • $\text{S}_2$
  • $\text{S}_3$
  • $\text{S}_4$
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The Correct Option is C

Solution and Explanation

Concept:
Feasible region = intersection of all inequalities. 

Step 1: Convert inequalities. 
$2x + 3y \ge 12 \Rightarrow$ region above the line 

$-y + x \ge -3 \Rightarrow y \le x + 3$ 

$x \le 4,\quad y \ge 3$ 

Step 2: Plot region.

  • Above $2x + 3y = 12$
  • Below $y = x + 3$
  • Left of $x = 4$
  • Above $y = 3$


Step 3: Intersection. 
Common overlapping region gives the feasible region. 

Step 4: Conclusion. 
From standard labeled diagram $\rightarrow \boxed{S_3}$

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