Concept:
Feasible region = intersection of all inequalities.
Step 1: Convert inequalities.
$2x + 3y \ge 12 \Rightarrow$ region above the line
$-y + x \ge -3 \Rightarrow y \le x + 3$
$x \le 4,\quad y \ge 3$
Step 2: Plot region.
Step 3: Intersection.
Common overlapping region gives the feasible region.
Step 4: Conclusion.
From standard labeled diagram $\rightarrow \boxed{S_3}$