Step 1: Analyze $x - y \ge 0$
This gives $x \ge y$, i.e., $y \le x$. The region lies on or below the line $y = x$.
Step 2: Analyze $x - 5y \le -5$
Rearranging, we get $5y \ge x + 5$ or $y \ge \frac{x}{5} + 1$.
The boundary line passes through the intercepts $(-5, 0)$ and $(0, 1)$. The region lies on or above this line.
Step 3: Non-negativity constraints
$x \ge 0,\; y \ge 0$ restrict the solution to the first quadrant.
Step 4: Conclusion
The feasible region is the area in the first quadrant that lies below the line $y = x$ and above the line $y = \frac{x}{5} + 1$. This corresponds to the unbounded region shown in figure (B).
Final Answer: (B)