Step 1: Identify reducing acid.
Among carboxylic acids, formic acid \((HCOOH)\) is unique because it contains an aldehydic hydrogen.
Step 2: Reason for reducing behaviour.
Formic acid can get oxidized to \(CO_2\), hence it reduces Tollens’ reagent and Fehling’s solution.
\[
HCOOH \rightarrow CO_2 + 2H^+ + 2e^-
\]
Step 3: Conclusion.
Thus formic acid shows reducing property.
Final Answer:
\[
\boxed{\text{formic acid}}
\]