Question:
The exhausted anion-exchange resin is regenerated with
The exhausted anion-exchange resin is regenerated with
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Anion-exchange resin is regenerated by dilute \(NaOH\), while cation-exchange resin is regenerated by dilute acid such as \(HCl\).
Updated On: May 7, 2026
- dilute \(NaOH\) solution
- dilute \(NaCl\) solution
- dilute \(HCl\) solution
- dilute \(Na_2SO_4\) solution
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The Correct Option is A
Solution and Explanation
Concept:
In the ion-exchange process, cation exchange resin and anion exchange resin are regenerated differently.
Step 1: Anion-exchange resin removes anions such as: \[ Cl^-,\ SO_4^{2-},\ NO_3^- \]
Step 2: The active form of anion-exchange resin is generally hydroxide form: \[ R-OH \]
Step 3: After exhaustion, the resin contains anions in place of \(OH^-\).
To regenerate it, we need to restore \(OH^-\) ions.
Step 4: Dilute \(NaOH\) provides \(OH^-\) ions: \[ NaOH \rightarrow Na^+ + OH^- \] Therefore, exhausted anion-exchange resin is regenerated using: \[ \boxed{\text{dilute }NaOH\text{ solution}} \]
Step 1: Anion-exchange resin removes anions such as: \[ Cl^-,\ SO_4^{2-},\ NO_3^- \]
Step 2: The active form of anion-exchange resin is generally hydroxide form: \[ R-OH \]
Step 3: After exhaustion, the resin contains anions in place of \(OH^-\).
To regenerate it, we need to restore \(OH^-\) ions.
Step 4: Dilute \(NaOH\) provides \(OH^-\) ions: \[ NaOH \rightarrow Na^+ + OH^- \] Therefore, exhausted anion-exchange resin is regenerated using: \[ \boxed{\text{dilute }NaOH\text{ solution}} \]
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