Question:

\(4\text{ g}\) of NaOH is dissolved in \(1.0\text{ L}\) solution. The pH of solution is

Show Hint

For strong bases, first find \([OH^-]\), then calculate \(pOH\), and use \(pH+pOH=14\).
  • \(13\)
  • \(1\)
  • \(12\)
  • \(7.4\)
Show Solution
collegedunia
Verified By Collegedunia

The Correct Option is A

Solution and Explanation

Mass of NaOH dissolved is: \[ 4\text{ g}. \] Molar mass of NaOH is: \[ 40\text{ g mol}^{-1}. \] Number of moles of NaOH: \[ \text{Moles}=\frac{4}{40}. \] \[ =0.1\text{ mol}. \] Volume of solution is: \[ 1.0\text{ L}. \] Molarity of NaOH: \[ M=\frac{0.1}{1.0}=0.1M. \] NaOH is a strong base, so it dissociates completely: \[ NaOH\rightarrow Na^+ + OH^-. \] Thus, \[ [OH^-]=0.1=10^{-1}. \] Now, \[ pOH=-\log[OH^-]. \] \[ pOH=-\log(10^{-1})=1. \] We know: \[ pH+pOH=14. \] Therefore, \[ pH=14-1. \] \[ pH=13. \] Hence, the pH of solution is: \[ 13. \]
Was this answer helpful?
0
0