Question:
How many moles of urea is present in \(250\text{ ml}\) of \(0.2M\) solution of it?
How many moles of urea is present in \(250\text{ ml}\) of \(0.2M\) solution of it?
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Molarity \(M=\frac{\text{moles}}{\text{volume in litres}}\). Always convert ml into litre before calculation.
Updated On: May 7, 2026
- \(0.03\)
- \(0.04\)
- \(0.05\)
- \(0.06\)
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The Correct Option is C
Solution and Explanation
We are given the molarity of urea solution:
\[
M=0.2M.
\]
The volume of solution is:
\[
V=250\text{ ml}.
\]
Convert volume from ml to litre:
\[
250\text{ ml}=\frac{250}{1000}\text{ L}=0.25\text{ L}.
\]
Molarity is defined as:
\[
M=\frac{\text{Number of moles of solute}}{\text{Volume of solution in litres}}.
\]
Therefore,
\[
\text{Number of moles}=M\times V.
\]
Substitute the values:
\[
\text{Number of moles}=0.2\times 0.25.
\]
\[
=0.05.
\]
Hence, the number of moles of urea present is:
\[
0.05.
\]
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