Question:
The equivalent weight of $KMnO₄$ for acid solution is ________.
The equivalent weight of $KMnO₄$ for acid solution is ________.
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The equivalent weight of $KMnO4$ for acid solution is ____.
Updated On: Apr 15, 2026
- 79
- 52.16
- 158
- 31.6
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The Correct Option is D
Solution and Explanation
Step 1: Concept
Equivalent weight = Molecular Weight / n-factor (change in oxidation state).
Step 2: Reaction in Acidic Medium
In acidic medium, $MnO_4^-$ is reduced to $Mn^{2+}$. The half-reaction is: $MnO_4^- + 8H^+ + 5e^- \rightarrow Mn^{2+} + 4H_2O$.
Step 3: n-factor
The oxidation state of Mn changes from +7 in $KMnO_4$ to +2 in $Mn^{2+}$. The change in oxidation state ($n$) is 5.
Step 4: Calculation
The molecular weight of $KMnO_4$ is 158 g/mol. Equivalent Weight $= 158 / 5 = 31.6$.
Final Answer: (D)
Equivalent weight = Molecular Weight / n-factor (change in oxidation state).
Step 2: Reaction in Acidic Medium
In acidic medium, $MnO_4^-$ is reduced to $Mn^{2+}$. The half-reaction is: $MnO_4^- + 8H^+ + 5e^- \rightarrow Mn^{2+} + 4H_2O$.
Step 3: n-factor
The oxidation state of Mn changes from +7 in $KMnO_4$ to +2 in $Mn^{2+}$. The change in oxidation state ($n$) is 5.
Step 4: Calculation
The molecular weight of $KMnO_4$ is 158 g/mol. Equivalent Weight $= 158 / 5 = 31.6$.
Final Answer: (D)
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