Question

The equivalent mass of Mohr's salt is:

• A. 392
• B. 31.6
• C. 278
• D. 156

Hint:

For Mohr's salt oxidation, $n\text{-factor} = 1$.

Answer 1

The Correct Option is A

Step 1: Concept
Equivalent wt. = $\frac{\text{Mol. wt.}}{\text{Change in oxidation number}}$.
Step 2: Analysis
In oxidation by $KMnO_{4}$, $Fe^{2+}$ becomes $Fe^{3+}$, a change of 1.
Step 3: Conclusion
Equivalent mass = $392 / 1 = 392$.
Final Answer: (A)