Question

The equivalent conductance of silver nitrate solution at 250°C for an infinite dilution was found to be \( 133.30 \, \text{S cm}^2 \text{equiv}^{-1} \). The transport number of \( \text{Ag}^+ \) ions in very dilute solution of \( \text{AgNO}_3 \) is 0.464. Equivalent conductances of \( \text{Ag}^+ \) and \( \text{NO}_3^- \) at infinite dilution are respectively

• A. \( 1952, 1333 \)
• B. \( 714, 619.4 \)
• C. \( 1952, 1333 \)
• D. \( 616, 1952 \)

Hint:

The equivalent conductance at infinite dilution is the sum of the individual conductances of the ions in solution.

Answer 1

The Correct Option is B

Step 1: Understanding the transport number and equivalent conductance.
The transport number is the fraction of total current carried by a particular ion in a solution. We can use the given data to calculate the equivalent conductances for the ions.

Step 2: Conclusion.
The equivalent conductance values for \( \text{Ag}^+ \) and \( \text{NO}_3^- \) at infinite dilution are \( 714 \, \text{S cm}^2 \) and \( 619.4 \, \text{S cm}^2 \), corresponding to option (2).