Concept:
The general equation of a plane passing through three points \( (x_1, y_1, z_1), (x_2, y_2, z_2), \) and \( (x_3, y_3, z_3) \) can be found using the determinant:
\[ \begin{vmatrix} x-x_1 & y-y_1 & z-z_1 \\ x_2-x_1 & y_2-y_1 & z_2-z_1 \\ x_3-x_1 & y_3-y_1 & z_3-z_1 \end{vmatrix} = 0 \]
Alternatively, you can test the given points in each option to find which one satisfies all three.
Step 1: Substitute points into the determinant form.
Using \( P_1(1, 0, 2) \):
\[ \begin{vmatrix} x-1 & y-0 & z-2 \\ -1-1 & 1-0 & 2-2 \\ 5-1 & 0-0 & 3-2 \end{vmatrix} = 0 \implies \begin{vmatrix} x-1 & y & z-2 \\ -2 & 1 & 0 \\ 4 & 0 & 1 \end{vmatrix} = 0 \]
Step 2: Expand the determinant to find the equation.
Expanding along the first row:
\[ (x-1)(1 - 0) - y(-2 - 0) + (z-2)(0 - 4) = 0 \]
\[ (x-1) + 2y - 4(z-2) = 0 \]
\[ x - 1 + 2y - 4z + 8 = 0 \]
\[ x + 2y - 4z + 7 = 0 \]