Question:

The equation of straight line passing through $(a,b,c)$ and parallel to x-axis is:

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Parallel to axis $\Rightarrow$ only one non-zero direction ratio.
Updated On: Apr 30, 2026
  • \(\frac{x-a}{1} = \frac{y-b}{0} = \frac{z-c}{0} \)
  • \(\frac{x-a}{0} = \frac{y-b}{1} = \frac{z-c}{1} \)
  • \(\frac{x-a}{1} = \frac{y-b}{0} = \frac{z-c}{1} \)
  • \(\frac{x-a}{1} = \frac{y-b}{1} = \frac{z-c}{-1} \)
  • \(\frac{x-a}{0} = \frac{y-b}{1} = \frac{z-c}{0} \)
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The Correct Option is A

Solution and Explanation

Concept: A line parallel to x-axis has direction vector: \[ (1,0,0) \]

Step 1:
Write symmetric form.
General form: \[ \frac{x-a}{l} = \frac{y-b}{m} = \frac{z-c}{n} \]

Step 2:
Substitute direction ratios.
\[ l=1,\; m=0,\; n=0 \] \[ \Rightarrow \frac{x-a}{1} = \frac{y-b}{0} = \frac{z-c}{0} \]
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