Step 1: Understanding the Question:
We are given the mathematical wave function for a wave propagating along a string under a mechanical tension $T = 0.4\text{ N}$. We need to compute the mass per unit length (linear mass density, $m$) of the string.
Step 2: Key Formula or Approach:
1.
Wave Speed from Wave Function: Compare the given function to the standard form $y = A \sin(kx + \omega t)$ to find the wave number $k$ and angular frequency $\omega$. The wave velocity is:
$$v = \frac{\omega}{k}$$
2.
Wave Speed on a Taut String: The velocity is physically governed by tension and linear density:
$$v = \sqrt{\frac{T}{m}} \implies m = \frac{T}{v^2}$$
Step 3: Detailed Explanation:
From the given wave equation $y = 4 \sin (3x + 60t)$, identify the kinematic coefficients:
Wave number, $k = 3\text{ rad/m}$
Angular frequency, $\omega = 60\text{ rad/s}$
Calculate the propagation speed ($v$) of the wave:
$$v = \frac{\omega}{k} = \frac{60}{3} = 20\text{ m/s}$$
Now, relate this speed to the tension expression to solve for the linear density $m$:
$$v = \sqrt{\frac{T}{m}} \implies v^2 = \frac{T}{m} \implies m = \frac{T}{v^2}$$
Substitute the given values ($T = 0.4\text{ N}$ and $v = 20\text{ m/s}$) into the equation:
$$m = \frac{0.4}{20^2} = \frac{0.4}{400} = \frac{4}{4000} = \frac{1}{1000} = 10^{-3}\text{ kg}\cdot\text{m}^{-1}$$
Step 4: Final Answer:
The mass per unit length of the string is $10^{-3}\text{ kg}\cdot\text{m}^{-1}$, which matches option (A).