Question:

The enthalpy of combustion of cyclohexane, cyclohexene and \(\text{H}_2\) are respectively \(-3920,-3800\) and \(-241\) KJ mol\(^{-1}\). The enthalpy of hydrogenation of cyclohexene is

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Use Hess law: hydrogenation = combustion of reactants minus combustion of product.
Updated On: Oct 1, 2026
  • \(-121\) KJ mol\(^{-1}\)
  • \(+121\) KJ mol\(^{-1}\)
  • \(-242\) KJ mol\(^{-1}\)
  • \(+242\) KJ mol\(^{-1}\)
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The Correct Option is A

Solution and Explanation

Step 1: Reaction
Cyclohexene \(+\text{H}_2\to\) cyclohexane.

Step 2: Hess law
\(\Delta H_{hyd}=\Delta H_c(\text{cyclohexene})+\Delta H_c(\text{H}_2)-\Delta H_c(\text{cyclohexane})\).
\[ =-3800-241-(-3920)=-121\text{ kJ mol}^{-1} \]

Step 3: Result
Option (A).

Final Answer:
\(\Delta H_{hyd}=-121\) kJ mol\(^{-1}\), option (A). \[ \boxed{\text{(A)}} \]
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