The energy stored in a capacitor is given by the formula:
\[
E = \frac{1}{2} C V^2
\]
Where: \( C = 10\,\mu\text{F} = 10 \times 10^{-6}\,\text{F} \) \( V = 100\,\text{V} \)
Substitute the values:
\[
E = \frac{1}{2} \times 10 \times 10^{-6} \times (100)^2 = \frac{1}{2} \times 10 \times 10^{-6} \times 10000 = \frac{1}{2} \times 0.1 = 0.05\,\text{J}
\]
So, the energy required is 0.05 J.
Was this answer helpful?
0
0
Top AP PGECET Instrumentation Engineering Questions