Question:

The energy of the electron in third excited state of the hydrogen atom is

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Excited state $x \Rightarrow n = x + 1$.
Updated On: Apr 27, 2026
  • -0.54 eV
  • -1.51 eV
  • -13.6 eV
  • -3.4 eV
  • -0.85 eV
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The Correct Option is

Solution and Explanation

Step 1: Concept
Energy in $n^{th}$ state is $E_n = \frac{-13.6}{n^2} \text{ eV}$.

Step 2: Meaning

"Third excited state" means the electron is in the $n = 4$ energy level.

Step 3: Analysis

$E_4 = \frac{-13.6}{4^2} = \frac{-13.6}{16} = -0.85 \text{ eV}$.

Step 4: Conclusion

Hence, the energy is -0.85 eV.
Final Answer: (E)
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