Question:

The electric field \((E)\) and magnetic field \((B)\) of an electromagnetic wave passing through vacuum are given by
\[ E=E_0\sin(kx-\omega t) \] \[ B=B_0\sin(kx-\omega t) \] Then the correct statement among the following is

Show Hint

For electromagnetic waves in vacuum: \[ E_0=cB_0 \] and \[ c=\frac{\omega}{k} \] Combining both relations gives the required result.
Updated On: Jun 22, 2026
  • \(E_0k=B_0\omega\)
  • \(E_0\omega=B_0k\)
  • \(E_0B_0=\omega k\)
  • \(E_0B_0=\dfrac{\omega}{k}\)
Show Solution
collegedunia
Verified By Collegedunia

The Correct Option is A

Solution and Explanation

Step 1: Recall the relation between electric and magnetic fields in an electromagnetic wave.
For an electromagnetic wave in vacuum, \[ E_0=cB_0 \] where \[ c=\text{speed of light} \]

Step 2: Write the relation between angular frequency and wave number.
For a wave, \[ c=\frac{\omega}{k} \] where \[ \omega=\text{angular frequency} \] and \[ k=\text{wave number} \]

Step 3: Substitute the value of \(c\).
Using \[ E_0=cB_0 \] we get \[ E_0=\frac{\omega}{k}B_0 \] Multiplying both sides by \(k\), \[ E_0k=B_0\omega \]

Step 4: Final conclusion.
Hence, the correct relation is \[ \boxed{E_0k=B_0\omega} \]
Was this answer helpful?
0
0

Top AP EAPCET Physics Questions

View More Questions