Question:
The distance between two consecutive points with phase difference of \(60^{\circ}\) in a wave of frequency \(n\) is \(x\) meter. The velocity with which wave is traveling is
The distance between two consecutive points with phase difference of \(60^{\circ}\) in a wave of frequency \(n\) is \(x\) meter. The velocity with which wave is traveling is
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A phase difference of \(60^{\circ}\) corresponds to a path difference of \(\lambda/6\).
Updated On: Oct 1, 2026
- \(nx\)
- \(2nx\)
- \(3nx\)
- \(6nx\)
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The Correct Option is D
Solution and Explanation
Step 1: Understanding the Concept:
A path difference of one wavelength \(\lambda\) corresponds to a phase difference of \(360^{\circ}\).
Step 2: Calculate:
A phase difference of \(60^{\circ}\) means a distance of \(\frac{60}{360}\lambda = \frac{\lambda}{6}\). So \(x = \frac{\lambda}{6}\) and \(\lambda = 6x\).
\[ v = n\lambda = 6nx \]
Final Answer:
The speed of the wave is \(6nx\), option (D). \[ \boxed{6nx} \]
A path difference of one wavelength \(\lambda\) corresponds to a phase difference of \(360^{\circ}\).
Step 2: Calculate:
A phase difference of \(60^{\circ}\) means a distance of \(\frac{60}{360}\lambda = \frac{\lambda}{6}\). So \(x = \frac{\lambda}{6}\) and \(\lambda = 6x\).
\[ v = n\lambda = 6nx \]
Final Answer:
The speed of the wave is \(6nx\), option (D). \[ \boxed{6nx} \]
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